問題描述
我有許多浮點數形式的數據文本文件.我正在尋找用 C++ 讀取它們的最快方法.如果這是最快的，我可以將文件更改為二進制文件.
I have numerous text files of data in the form of float numbers. I'm looking for the fastest way to read them in C++. I can change the file to binary if that's the fastest.
如果您能給我提示或將我推薦給一個有完整解釋的網站，那就太好了.我不知道是否有任何庫可以快速完成工作.即使有任何開源軟件可以完成這項工作，也會有所幫助.
It would be great if you could give me hint or refer me to a website with complete explanation. I don't know whether there is any library that does the work fast. Even if there is any open source software that does the work, that would be helpful.
推薦答案
擁有二進制文件是最快的選擇.您不僅可以在單個操作中使用原始 istream::read 直接在數組中讀取它(非常快)，而且如果您的操作系統支持，您甚至可以將文件映射到內存中；您可以在 POSIX 系統上使用 open/mmap，CreateFile/CreateFileMapping/MapViewOfFile在 Windows 上，甚至是 Boost 跨平臺解決方案(感謝 @Cory Nelson 指出).
Having a binary file is the fastest option. Not only you can read it directly in an array with a raw istream::read in a single operation (which is very fast), but you can even map the file in memory if your OS supports it; you can use open/mmap on POSIX systems, CreateFile/CreateFileMapping/MapViewOfFile on Windows, or even the Boost cross-platform solution (thanks @Cory Nelson for pointing it out).
快速&臟示例，假設文件包含一些 float 的原始表示:
Quick & dirty examples, assuming the file contains the raw representation of some floats:
正常"閱讀:
#include <fstream>
#include <vector>
// ...
// Open the stream
std::ifstream is("input.dat");
// Determine the file length
is.seekg(0, std::ios_base::end);
std::size_t size=is.tellg();
is.seekg(0, std::ios_base::beg);
// Create a vector to store the data
std::vector<float> v(size/sizeof(float));
// Load the data
is.read((char*) &v[0], size);
// Close the file
is.close();
使用共享內存:
#include <boost/interprocess/file_mapping.hpp>
#include <boost/interprocess/mapped_region.hpp>
using boost::interprocess;
// ....
// Create the file mapping
file_mapping fm("input.dat", read_only);
// Map the file in memory
mapped_region region(fm, read_only);
// Get the address where the file has been mapped
float * addr = (float *)region.get_address();
std::size_t elements = region.get_size()/sizeof(float);
這篇關于讀取輸入文件，最快的方法?的文章就介紹到這了，希望我們推薦的答案對大家有所幫助，也希望大家多多支持html5模板網！