問題描述
我有這樣的價值觀:
long millis = 11400000;int 常數 = 86400000;雙分辨率 = 毫/常數；問題是:為什么 res 等于 0.0(而不是 ca. 0.131944)?它存儲在 double 中，所以應該沒有四舍五入吧?
當你使用二元運算符時，兩個參數的類型應該相同，結果也應該是它們的類型.當你想劃分 (int)/(long) 它變成 (long)/(long) 結果是 (long).您應該將其設為 (double)/(long) 或 (int)/(double) 以獲得雙重結果.由于 double 大于 int 和 long，所以 int 和 long 在 (double)/(long) 和 (int)/(double)
I have values like this:
long millis = 11400000;
int consta = 86400000;
double res = millis/consta;
The question is: why res equals 0.0 (instead of ca. 0.131944)? It's stored in double so there should be no rounding right?
When you are using a binary operator, both arguments should be of a same type and the result will be in their type too. When you want to divide (int)/(long) it turns into (long)/(long) and the result is (long). you shouldmake it (double)/(long) or (int)/(double) to get a double result. Since double is greater that int and long, int and long will be turned into double in (double)/(long) and (int)/(double)
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