問題描述

我需要根據上一次調用的數據連續進行 6 次 ajax 調用.我將每個調用嵌套在上一個調用的成功中.我的問題是有什么好的方法來格式化代碼，這樣它就不會在我的編輯器中出現一百萬行?

I have a requirement to make 6 ajax calls in succession based on data from the previous call. I am nesting each call in the success of the previous call. my question is what are some good ways to format the code so that it doesnt end up a million rows across my editor?

 $.ajax({
                type: "POST",
                url: "someScript/someScript.php",
                data: form + "&func=build",
                success: function (result) {
                 if (result == "ok")
                 {
                   $.ajax({
                   type: "POST",
                   url: "someScript/someScript.php",
                   data: form + "&func=someOtherFunc",
                   success: function (result) {
                        if (result == "ok")
                        {
                          $.ajax({
                           type: "POST",
                           url: "someScript/someScript.php",
                           data: form + "&func=someOtherFunc",
                           success: function (result) {
                           if (result == "ok")
                           {
                             .....and so on
                           }
                           })
                         }
                      })
                    })
                   }
                 })

忽略括號，語法對于這個問題并不重要.

ignore brackets, syntax isnt important for this question.

推薦答案

你可以這樣做

function ajaxCall1(){
    $.ajax({
        success: function(){
            ajaxCall2();
        }
    });
}
function ajaxCall2(){
    $.ajax({
        success: function(){
            ajaxCall3();
        }
    });
}
function ajaxCall3(){
    $.ajax({
        success: function(){
            ajaxCall4();
        }
    });
}

這篇關于jquery嵌套ajax調用格式化的文章就介紹到這了，希望我們推薦的答案對大家有所幫助，也希望大家多多支持html5模板網！